This Crazy Syntax Lets You Get An Array Element's Type
Learn how to extract the type of an array element in TypeScript using the powerful Array[number]
trick.
Any any
in a codebase is a cause for concern. That's because it disables type checking on the thing it's assigned to.
If you pass an any
to a function parameter, you then can't guarantee anything about that function parameter:
const groupBy = (arr: any[], key: any) => {
const result: any = {};
arr.forEach((item) => {
// How do we know that item is an object?
// Or that it has a property the same
// as the key we pass in?
const resultKey = item[key];
if (result[resultKey]) {
result[resultKey].push(item);
} else {
result[resultKey] = [item];
}
});
return result;
};
An any
can also 'leak' across your application.
If we use this function, we're going to get back any
and disable type checking in even more places.
Can you spot the 2 errors below?
const array = [
{ name: "John", age: 20 },
{ name: "Jane", age: 20 },
{ name: "Jack", age: 30 },
];
const result = groupBy(array);
// result is any!
result[20].foreach((item) => {
// item is any!
console.log(item.name, item.age);
});
So why would an any
be added to a codebase in the first place?
One reason could be that you're trying to solve a bug you don't understand.
TypeScript has plenty of hard edges that can feel unintuitive for beginners.
const keys = ["a", "b"];
const obj = {};
for (const key of keys) {
// Element implicitly has an 'any' type because
// expression of type 'string' can't be used to
// index type '{}'.
obj[key] = key;
}
const keys = ["a", "b"];
// Phew, no more error
const obj: any = {};
for (const key of keys) {
obj[key] = key;
}
By the way, the best way to solve and error like the above is either with a Record, or with an as
type - depending on how specific a type you want obj
to be:
const keys = ["a", "b"];
// obj will be typed as a record where its
// properties can be any string
const obj: Record<string, string> = {};
for (const key of keys) {
obj[key] = key;
}
const keys = ["a", "b"] as const;
// obj will now be typed with the keys 'a' and 'b'
const obj = {} as Record<
typeof keys[number],
string
>;
for (const key of keys) {
obj[key] = key;
}
Another way any
s creep into your code is when you don't use enough generics.
Imagine, for a moment, that TypeScript didn't have generics. How would you actually type this function?
// How on earth do you type this function?
const groupBy = (arr, key) => {
const result = {};
arr.forEach((item) => {
const resultKey = item[key];
if (result[resultKey]) {
result[resultKey].push(item);
} else {
result[resultKey] = [item];
}
});
return result;
};
Let's try our hardest to avoid using any
.
We know that the members of the array must be objects, so let's start with a Record<string, unknown>[]
type:
const groupBy = (
arr: Record<string, unknown>[],
key: string
) => {
const result = {};
arr.forEach((item) => {
const resultKey = item[key];
if (result[resultKey]) {
result[resultKey].push(item);
} else {
result[resultKey] = [item];
}
});
return result;
};
But we immediately run into issues, because we've said that the values of each item
is unknown, and you can't use unknown
to index into result
:
const groupBy = (
arr: Record<string, unknown>[],
key: string
) => {
const result = {};
arr.forEach((item) => {
const resultKey = item[key];
// Type 'unknown' cannot be used as an index type.
if (result[resultKey]) {
// ^^^^^^^^^
result[resultKey].push(item);
} else {
result[resultKey] = [item];
}
});
return result;
};
So, we try and cast item[key]
to string, but this results in even more issues:
const groupBy = (
arr: Record<string, unknown>[],
key: string
) => {
const result = {};
arr.forEach((item) => {
const resultKey = item[key] as string;
// No index signature with a parameter of
// type 'string' was found on type '{}'.
if (result[resultKey]) {
//^^^^^^^^^^^^^^^^^
result[resultKey].push(item);
} else {
result[resultKey] = [item];
}
});
return result;
};
The way to fix this is to add a type annotation to result, to represent the type that we're getting back:
const groupBy = (
arr: Record<string, unknown>[],
key: string
) => {
const result: Record<string, unknown[]> = {};
arr.forEach((item) => {
const resultKey = item[key] as string;
if (result[resultKey]) {
result[resultKey].push(item);
} else {
result[resultKey] = [item];
}
});
return result;
};
No more errors, but the result of groupBy
is now always Record<string, unknown[]>
:
const array = [
{ name: "John", age: 20 },
{ name: "Jane", age: 20 },
{ name: "Jack", age: 30 },
];
// result is Record<string, unknown[]>
const result = groupBy(array, "age");
Is this preferable to using any
?
In one sense, HELL YES.
This gives us proper type-safety on the values of the result, meaning you will catch errors like misspelled array methods:
const result = groupBy(array, "age");
// Property 'foreach' does not exist on type
// 'unknown[]'. Did you mean 'forEach'?
result[20].foreach((item) => {});
But in another sense, we've just changed the problem.
Now instead of having any
s spreading across our app, we have unknown
s.
The unknown
type is extremely "yelly". It errors whenever you access a property or assign it to something that isn't unknown
:
const result = groupBy(array, "age");
result[20].forEach((item) => {
// 'item' is of type 'unknown'.
item.name;
// Type 'unknown' is not assignable to type
// '{ name: string; age: number; }'.
const typedItem: { name: string; age: number } =
item;
});
You could go further with validation if you wanted to, but since we already know for sure that item
has a name
and an age
it becomes pointless runtime bloat:
result[20].forEach((item) => {
if (
typeof item === "object" &&
item &&
"age" in item &&
"name" in item &&
typeof item.age === "number" &&
typeof item.name === "string"
) {
// Hooray, it's a string!
item.name;
// Hooray, it's a number!
item.age;
}
});
So to recap:
Unnecessary any
s in your codebase are bad because they cause bugs.
Unnecessary unknown
s in your codebase are bad because they bloat your runtime code with boilerplate.
And from the steps we've seen above, typing a utility function to return the unknown
s in the right place is NOT easy.
The way out of this Catch-22 is generics.
The code below is extremely complex, but it perfectly describes the behaviour of the function.
Consumers of the function don't need to worry about any
s or unknown
s. It behaves exactly as they expect to:
const groupBy = <
TObj extends Record<string, unknown>,
TKey extends keyof TObj
>(
arr: TObj[],
key: TKey
) => {
const result = {} as Record<
TObj[TKey] & PropertyKey,
TObj[]
>;
arr.forEach((item) => {
const resultKey = item[key] as TObj[TKey] &
PropertyKey;
if (result[resultKey]) {
result[resultKey].push(item);
} else {
result[resultKey] = [item];
}
});
return result;
};
const result = groupBy(array, "age");
result[20].forEach((item) => {
// No errors, no validation needed!
console.log(item.name, item.age);
});
The big takeaway here is that if you're concerned about any
s in your codebase, you need to know generics.
Total TypeScript Core Volume has an entire workshop module dedicated to generics that will give you the knowledge and understanding to avoid implementing suboptimal code that brings uncertainty into your app.
An `unknown` can't always fix an `any`
Learn how to extract the type of an array element in TypeScript using the powerful Array[number]
trick.
Learn how to publish a package to npm with a complete setup including, TypeScript, Prettier, Vitest, GitHub Actions, and versioning with Changesets.
Enums in TypeScript can be confusing, with differences between numeric and string enums causing unexpected behaviors.
Is TypeScript just a linter? No, but yes.
It's a massive ship day. We're launching a free TypeScript book, new course, giveaway, price cut, and sale.
Learn why the order you specify object properties in TypeScript matters and how it can affect type inference in your functions.